[DISCUSSION] Locations

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deagol
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Post by deagol »

CrazyIvan1745 wrote: But yeah I also can't wait to find out on the building bethy thinks is on Wilshire. I can't find it on google earth but that doesn't mean its not there if it isn't I search atarting around that area.
Ivan, the address is posted in the thread for that video.

9701 Willshire Blvd, Beverly Hills. Google earth had no problem finding it for me.
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CrazyIvan1745
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Post by CrazyIvan1745 »

Heres my search in the zipcode area 11413

http://s151.photobucket.com/albums/s153 ... h11413.flv

(added music for entertainment)

I only saw 2 houses with pools in this one and my much more thourough (<-can't spell) search.

(Also I am talking about this building:)
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CrazyIvan1745
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Post by CrazyIvan1745 »

Well while I was waiting for something to happen I decided to make a quick little vid of LA on google earth (fraps was being laggy but whatever) anyways the song is the begging of a song where I get the name CrazyIvan from. so, yeah... I am bored...I wish they would put up another vid for me to search for stuff on...

http://s151.photobucket.com/albums/s153 ... ngeles.flv
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tiltingwindward
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Post by tiltingwindward »

Just jumping in here for a second...

...you all should be grateful that you have a kind, generous, self-sacrificing mod like Apo around, because I (and I believe I speak for Panda and Tiger here too) fully intend to let you stew in your own sexy prime juices. If you want to stay up all night jittery on caffeine trying to figure out whether 10033 is some sort of obscure mathematical Holy Grail, and whether that makes it the number of the Beast, I promise to sit back and watch. With popcorn. And M&Ms.

So please, be my guest. I've got all night. :)
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CrazyIvan1745
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Post by CrazyIvan1745 »

lol
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deagol
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Post by deagol »

tiltingwindward wrote:...
So please, be my guest. I've got all night. :)
Oh dear, you didn't just drop that gauntlet, did you? Are you sure you want this?

:smt025
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tiltingwindward
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Post by tiltingwindward »

I'm just saying...I've got nothing but time. And the ability to leave this thread, of course. :)

That gauntlet on the floor? I think it's yours.
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deagol
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Post by deagol »

/me picks up gauntlet...

Ok, here we go. 10033 is the Holy Grail. Yep.

First, lets say it's not 10033, but 100.33. Now, bear with me here for a sec.

100.33
100 +33/100
100 +1/(100/33)
100 +1/(3+1/33)
[100,3,33]

What I've done here is reformated the decimal number into a continued fraction, which are useful for representing real numbers with infinite decimal digits after the decimal point, including some numbers with non-periodic decimal digits (irrational). A number expressed in continued fraction is of the form a+1/(b+1/(c+1/(d+1/...))) etc., where the list form is obtained by replacing the '+1/(' pattern that repeats all the time with a comma, and putting the remaining list of numbers inside brackets. Thus, [a,b,c,d,...]. An easier way to visualize it is:

Code: Select all

             1
a + -------------------  =  [a,b,c,d,...]
               1
     b + -------------
                 1
          c + -------
               d + ... etc.
But that takes a lot of space. The first number 'a' can be any integer, but all the others must be positive integers.

Notice how in that intertpretation of 100.33 all the numbers in the continued fraction list form use the same digits, 0, 1, and 3. This is not always the case for a continued fraction, of course, regardless of which digits are used in the decimal representation. Even with the same 10033, take an alternative interpretation:

1.0033
1+33/10000
1+1/(10000/33)
1+1/(303+1/33)
[1,303,33]

Uh... ok that one also worked with every digit being 0, 1, or 3. I must have been looking for another one. Lets try this:

10.033
10+33/1000
10+1/(1000/33)
10+1/(30+10/33)
10+1/(30+1/(33/10))
10+1/(30+1/(3+3/10))
10+1/(30+1/(3+1/(10/3)))
10+1/(30+1/(3+1/(3+1/3)))
[10,30,3,3,3]

Huh... well that took a bit more work but, I'll be damned, it still uses the same digits... hang on I got to show you this is not always the case:

1003.3
1003+3/10
1003+1/(10/3)
1003+1/(3+1/3)
[1003,3,3]

Oh dear... only one more to try or I'll have to eat my words with this...

.10033
0+10033/100000
0+1/(100000/10033)
0+1/(9+9703/10033) ahh there we go, we got a 9!...
0+1/(9+1/(10033/9703))
0+1/(9+1/(1+330/9703))
0+1/(9+1/(1+1/(9703/330)))
0+1/(9+1/(1+1/(29+133/330)))
0+1/(9+1/(1+1/(29+1/(330/133))))
0+1/(9+1/(1+1/(29+1/(2+64/133)))) holy crap this is a long one!
0+1/(9+1/(1+1/(29+1/(2+1/(133/64)))))
0+1/(9+1/(1+1/(29+1/(2+1/(2+5/64)))))
0+1/(9+1/(1+1/(29+1/(2+1/(2+1/(64/5))))))
0+1/(9+1/(1+1/(29+1/(2+1/(2+1/(12+4/5))))))
0+1/(9+1/(1+1/(29+1/(2+1/(2+1/(12+1/(5/4)))))))
0+1/(9+1/(1+1/(29+1/(2+1/(2+1/(12+1/(1+1/4))))))) phew!
[0,9,1,29,2,2,1,1,12,1,4]

Aha, so there you have it. It could end up being any numbers. But more appropriately, if 10033 was meant to be represented with a continued fraction, it probably means that the actual number has infinite digits after the decimal point. One possibility would be 100.333333... with indefenitely many 3's:

100.333333333...
100+1/3
[100,3]

Another one might be:

1.0033003300330033...
1+1/303
[1,303]

If you're up to it you can figure out other similar interpretations with infinite decimal digits, but I'm tired of all these fractions. Oh, uh, alright. Just one more I just thought of. Last one, I promise:

100/33
3+1/33
[3,33]

Ha, that's it! Remove the comma and you get 333, the triple trinity, or a half-beast... ;)

There, I'm done and fried.
Last edited by deagol on Mon Feb 19, 2007 1:01 pm, edited 3 times in total.
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Ziola
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Post by Ziola »

I hate you
It's official!! I'm getting married September 28, 2007!!
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Post by impulse »

:shock:

](*,)
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Kasdeja
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Post by Kasdeja »

:shock: slowly backs out of thread
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Onewen
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Post by Onewen »

OMG! Who are you? Rainman??? :shock:
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Kasdeja
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Post by Kasdeja »

These definitely aren't my underwear...
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sphinx
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Post by sphinx »

I'm scared.

Hold me.
ladron121
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Post by ladron121 »

sphinx wrote:I'm scared.

Hold me.
Anytime ;)
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